Suppose we are given triangle ABC, and let D lies in (AB) be such that |angleDCA| = |angleABC|.
Prove that d(A, C) is the mean proportional between d(A, B) and d(A, D).
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thanks, but I don't understand how
triange ABC ~ triangle ACD
Originally Posted by jenjen thanks, but I don't understand how
triange ABC ~ triangle ACD the symbol ~ is a notation for similar, i.e. when he wrote , then he meant that the two triangles are similar..
I understand that symbol, but I just don't know how they can be similar. Thanks
Ohhhhhh, I got it now. kool!
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