1. ## Geometry problem

Can somebody help me with this?

2. ## Re: Geometry problem

You can determine D easily enough to be 114 deg.
You can further determine that this is an isoceles triangle and that AC=BC.

Then you can use the law of sines to get

$\dfrac{\sin(114deg)}{BC}=\dfrac{\sin(48deg)}{DC}$

$\dfrac{\sin(x)}{DC}=\dfrac{\sin(174deg-x)}{AC}$

$\dfrac{\sin(114deg)}{\sin(48deg)}=\dfrac{BC}{DC}= \dfrac{AC}{DC}=\dfrac{\sin(174deg-x)}{\sin(x)}$

You can solve this equation to obtain

Spoiler:
$x=24deg$

3. ## Re: Geometry problem

thanks a lot man