How. Do I find the height of a pyramid when I know the length of an edge (4 m) and the edge of the square base (5.66)? Hope someone can help.
The base is a square with edges of length 5.66. Using the Pythagorean theorem, a diagonal has length $\displaystyle 5.66\sqrt{2}$. The distance from one corner of the square base to the center is half of that $\displaystyle 2.83\sqrt{2}$. The "height", h, is one leg of a right triangle having hypotenuse 4 and one leg of length $\displaystyle 2.83\sqrt{2}$. Use the Pythagorean theorem again to find h.