# Finding height of a pyramid

The base is a square with edges of length 5.66. Using the Pythagorean theorem, a diagonal has length $5.66\sqrt{2}$. The distance from one corner of the square base to the center is half of that $2.83\sqrt{2}$. The "height", h, is one leg of a right triangle having hypotenuse 4 and one leg of length $2.83\sqrt{2}$. Use the Pythagorean theorem again to find h.