Given: ABCD is a parallelogram; BM=MC how to prove: S(ABM) = 1 4th S(ABCD) ?
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Originally Posted by nataku Given: ABCD is a parallelogram; BM=MC how to prove: S(ABM) = 1 4th S(ABCD) ? Let $N$ be the midpoint of $\overline{AD}$ then draw $\overline{MN}$. Then you have four congruent triangles.
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