Here is the question: Gyazo - 8d2dd59242fb7fa392dbdc6fa84e79a5.png (question 25)

Here is my work: Gyazo - 9fcbe6021e7df14bd5c03df38dd82d3a.png

I could've used A=.5*b*h (regular area formula for triangle) but since I've been using A=.5*apothem*perimeter, I figured I'd continue using it. My final answer was 32in squared.

Used 30-60-90 special right triangle rules etc. If something isn't clear in my scrap, let me know.