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Math Help - Just a quick proprtion question....

  1. #1
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    Just a quick proprtion question....

    How do I solve for y?



    Thanks
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  2. #2
    Super Member angel.white's Avatar
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    If I interpret your graph correctly, then this is just the Pythagorean theorem

    a^{2}+b^{2}=c^{2}

    Where a and b are the length and height your right triangle, and c is the hypotenuse.

    So your example, is 8 units long and 1.6 units high (4.6-3)

    Then
    8^{2}+1.6^{2}=c^{2}

    64+2.56=c^{2}

    66.56=c^{2}

    \sqrt{66.56}=c

    8.51843\approx c
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  3. #3
    is up to his old tricks again! Jhevon's Avatar
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    could y have been the height of the vertical line that splits the base into 5 and 3 perhaps

    it is not very clear to me. i guess thinking of y as the hypotenuse makes sense. it is up to the poster to clarify
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  4. #4
    Super Member angel.white's Avatar
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    If that is the case, I would find the slope of the hypotenuse by dividing the y value by the x value:

    slope = \frac{1.6}{8} = .2

    Find the distance from the angle to the line
    8-5=3

    Multiply the slope by the distance to find the height off of the base of the triangle
    3*.2=.6

    Add the distance from the base of the shape to the base of the triangle (this is given in the picture as 3)

    .6+3=3.6

    And so the height of the line in the middle of the shape is 3.6
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  5. #5
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    Quote Originally Posted by angel.white View Post
    If that is the case, I would find the slope of the hypotenuse by dividing the y value by the x value:

    slope = \frac{1.6}{8} = .2

    Find the distance from the angle to the line
    8-5=3

    Multiply the slope by the distance to find the height off of the base of the triangle
    3*.2=.6

    Add the distance from the base of the shape to the base of the triangle (this is given in the picture as 3)

    .6+3=3.6

    And so the height of the line in the middle of the shape is 3.6
    Yes!! Thank you.. this is it
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