OP, you really have to show some working!!!
Hello, vegasgunner!
Four diagonals of a regular octagon with the length of 2
intersect as shown. .Find the area of the shaded region.
Are there 4 right triangles that are not shaded? , Yes!Code:B 2 C o * * * o 2 * * * 2 * * * * * * A o * * * * * * * * * * * o D * *:::::::::::::::* * 2 * *:::::::::::::::* * 2 * *:::::::::::::::* * H o * * * * * * * * * * * o E * * * * * * * * * o * * * o G F
The shaded region is the rectangle minus the two right triangles.
The right triangles have legs of length 2.
You can find their total area.
The rectangle has base and height
We can find the length of the base with this diagram.
The base is:Code:B 2 C o * * * * * o * : : * 2 * : : * 2 * :x :x * * : : * * 45^{o} : : 45^{o}* A o * * * * * * * * * * * o D x 2 x
You should be able to determine
Got it?