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Math Help - octagon shaded ara help

  1. #1
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    octagon shaded ara help



    are there 4 right triangles that are not shaded, I am confused please help
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  2. #2
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    Re: octagon shaded ara help

    OP, you really have to show some working!!!
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    Re: octagon shaded ara help

    Quote Originally Posted by LimpSpider View Post
    OP, you really have to show some working!!!
    thanks for the help and your English is incorrect the correct term is you really have to show some work
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    Re: octagon shaded ara help

    Quote Originally Posted by vegasgunner View Post
    thanks for the help and your English is incorrect the correct term is you really have to show some work
    LimpSpider's English is fine. "Working" (or rather, "Working Out") can be a noun as well as a verb. And the OP is entirely correct. Just how many questions are you expecting us to do from your homework which you have not even attempted yourself?
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  5. #5
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    Re: octagon shaded ara help

    Hello, vegasgunner!


    Four diagonals of a regular octagon with the length of 2
    intersect as shown. .Find the area of the shaded region.
    Code:
                 B    2    C
                  o * * * o
             2  *   *       *  2
              *       *       *
            *           *       *
        A o * * * * * * * * * * * o D
          * *:::::::::::::::*     *
        2 *   *:::::::::::::::*   * 2
          *     *:::::::::::::::* *
        H o * * * * * * * * * * * o E
            *       *           *
              *       *       *
                *       *   *
                  o * * * o
                 G         F
    Are there 4 right triangles that are not shaded? , Yes!

    The shaded region is the rectangle ADEH minus the two right triangles.

    The right triangles have legs of length 2.
    You can find their total area.

    The rectangle has base AD and height AH = 2.

    We can find the length of the base with this diagram.

    Code:
                     B      2      C
                      o * * * * * o
                    * :           : *
               2  *   :           :   *  2
                *     :x          :x    *
              *       :           :       *
            * 45o     :           :      45o*
        A o  *  *  *  *  *  *  *  *  *  *  *  o D
                x           2           x
    The base is: AD \:=\:2 + 2x

    You should be able to determine x.


    Got it?
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