Hi Fentonjc,
I am going to assume that /ADC means angle ADC
and DB ' AC means DB bisects AC (the only other alternative that I can think of is that DB is perpendicular to AC and the proof would be similar)
Draw the picture first of course
Let X be the intersection of DB and AC
Consider triangle ADX and triangle CDX
you can prove that these 2 triangles are congruent and hence show that AX=CX
then give a concluding statement and you are finished.
Is that enough help?
Melody.
Hello, Fentonjc!
I am getting better at Mathematical Forensics.
I think I understand the problem . . .
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We are given: .Code:D * /|\ / | \ / | \ / | \ / | \ / | \ / | \ A * - - - * - - - * C B
We are told that bisects
Then: .
Also: . (Identity)
So: . (s.a.s.)
Hence: . (corresponding parts)
We see: .
Since
Therefore: .
I tried to attach the actual picture. Then it has a box that has 2 sides ones says statements and the other says reasons.
it is a triangle that has a D on top and A B C on the bottom and it also has a 1 and 2 inside the triangle under the D