Results 1 to 4 of 4

Math Help - Need help please

  1. #1
    Newbie
    Joined
    Mar 2006
    Posts
    3

    Need help please

    This question has been giving me grief all morning, could anyone help me out:

    If the moon's diameter is 3,476 km and its average distance from Earth is 384,000 km, use the small angle formula to calculate the Moon's size in the sky.

    angular size / 206,265" = diameter/ distance

    Report your answer to the nearest arc-second (")
    Follow Math Help Forum on Facebook and Google+

  2. #2
    Newbie
    Joined
    Mar 2006
    Posts
    3
    oh yeah and then:

    Convert your answer to the previous question to find the Moon's size in arc-minutes (')

    Give your answer to the nearest arc-minute (no decimal places)

    Your answer should be close to the equivalent of 1/2 degree.

    Follow Math Help Forum on Facebook and Google+

  3. #3
    Grand Panjandrum
    Joined
    Nov 2005
    From
    someplace
    Posts
    14,972
    Thanks
    4
    Quote Originally Posted by forza85
    This question has been giving me grief all morning, could anyone help me out:

    If the moon's diameter is 3,476 km and its average distance from Earth is 384,000 km, use the small angle formula to calculate the Moon's size in the sky.

    angular size / 206,265" = diameter/ distance

    Report your answer to the nearest arc-second (")
    angular size=206265*dia/dist=206265*3476/384000~=1867 seconds of arc

    RonL
    Follow Math Help Forum on Facebook and Google+

  4. #4
    Grand Panjandrum
    Joined
    Nov 2005
    From
    someplace
    Posts
    14,972
    Thanks
    4
    Quote Originally Posted by forza85
    oh yeah and then:

    Convert your answer to the previous question to find the Moon's size in arc-minutes (')

    Give your answer to the nearest arc-minute (no decimal places)

    Your answer should be close to the equivalent of 1/2 degree.

    1867 secods of arc= 1867/60 minutes of arc ~=31 minutes of arc

    31 minutes of arc=31/60 degrees ~= 1/2 degree.

    RonL
    Follow Math Help Forum on Facebook and Google+


/mathhelpforum @mathhelpforum