
Isosceles Triangle
Hey Guys!
Just to be sure. I don't know if I am correct since I can't view the answer on the back of the book
An isosceles right triangle has a hypotenuse of length
10 cm. How long is each leg?
So I have an isosceles triangle
one 90 degree angle and two angles with the same measure.
hypotenuse is 10 so i assume 10^2 = 100
others are 5√2 (bootleg radical sign) I think since I have the hypotenuse of a 45 45 degree right angle has a base of x and hypotenuse x√2.
Not sure if this is correct.

Re: Isosceles Triangle
yup, there's a couple ways to do this, both based on the Pythagorean formula.
A^2+B^2=C^2
where C is the hypotenuse, A and B are the legs.
But, since the triangle is isosceles, A=B, so
2*A^2=C^2
substituting...
2*A^2 = (10)^2 = 100
A^2 = 50 = 25*2
A= 5*sqrt(2)
or, if you happen to know that the sides of a 454590 triangle have the ratio 1:1:sqrt(2), you can jump straight to
A*sqrt(2) = 10
A = 10/sqrt(2) = 5*sqrt(2)

Re: Isosceles Triangle