Math Help - center of circle with equation x^2+14x+y^2-6y+53=0

1. center of circle with equation x^2+14x+y^2-6y+53=0

center of circle with equation x^2+14x+y^2-6y+53=0

2. Re: center of circle with equation x^2+14x+y^2-6y+53=0

Originally Posted by vegasgunner
center of circle with equation x^2+14x+y^2-6y+53=0
$x^2+14x+49+y^2-6y+9=-53+49+9$

3. Re: center of circle with equation x^2+14x+y^2-6y+53=0

would it be (-7,3)??

4. Re: center of circle with equation x^2+14x+y^2-6y+53=0

Originally Posted by vegasgunner
would it be (-7,3)??
You should know at least that much. Look up definitions,