Why would that method be wrong. That's exactly what you have to do. Get the (x, y) co-ordinates when t = p and when t = q, use these to get the equation of your line.
Hi everyone!
I'm new here, and I'll like to ask for help for the following questions. Could someone please provide some general guidelines and hints on how to solve these questions but not give an answer to the questions themselves?
Q1: A curve has parametric equations x=2t^{2}, y=4t. Find the equation of the chord joining the points on the curve where t=p and t=q. I have no idea how to even start solving this. I know that the Cartesian equation of the curve is y^{2}=8x. I have tried substituting in p into x=2t^{2} and q into y=4t, but that method is wrong.
Q2: This question is similar. Find the equations of the chord AB where at A (t=t_{1}) and at B (t=t_{2}). AB is on a curve with parametric equations x=ct and y=c/t.
I thought that since at AB the variable is in t, I would eliminate the variable c. Therefore, I came up with yt^{2}=x. I found that with this equation, at A, x=y(t_{1})^{2}, y=((t_{1})^{2})/x, and at B, x=y(t_{2})^{2}, y=((t_{2})^{2})/x. Using these two coordinates, the gradient will be 1/(xy). However, this can never get the answer, which is t_{1}t_{2}y+x=c(t_{1}+t_{2}). How do I get the c inside the answer? Or is it because I'm doing something wrong?
Any help is appreciated!
Hello, LimpSpider!
It looks like you don't understand parametric equations . . .
Q1: A curve has parametric equations: .
Find the equation of the chord joining the points on the curve where and
I have tried substituting in p into x=2t^{2} and q into y=4t, but that method is wrong. . Of course!
You have: .
So where is the chord?
And there are the two points . . .
Hey everyone! Thanks a bunch again for all the answers. If I understand correctly, I must substitute t=variable into BOTH the x and y parametric equations to get the coordinate of one point. I was wrongly thinking all this time that p is a substitute just for x and q for y. . After getting the coordinates, I'm sure I'll be able to get the equations. Thanks again!
(Edit: I have indeed arrived at all the correct answers!! )