The starting point is to see that angle CAD is equal to the angle CBA.

(It's a basic angle property of a circle.)

After that it's a routine similar triangles job.

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- September 19th 2013, 03:43 AM #1

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## Hi All! Need help with this question please! Thank you!

Hi all! Thank you for taking the time to help me!

I can't seems to start this question. Hope someone can guide me in the right direction, thanks!

Attached is a picture of the diagram.

The question is

Given AD is tangent to the circle at A.

BCD is a straight line that intersects the tangent at D.

DHK is the angle bisector of Angle ADC and it cuts AC at H and AB at K.

a) show that HD * BD = KD * AD

* meaning multiply/product.

b) show that triangle AHK is an isosceles triangle.

Thank you!

- September 19th 2013, 02:23 PM #2

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- September 19th 2013, 05:44 PM #3

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- September 20th 2013, 07:29 AM #4

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