The starting point is to see that angle CAD is equal to the angle CBA.
(It's a basic angle property of a circle.)
After that it's a routine similar triangles job.
Hi all! Thank you for taking the time to help me!
I can't seems to start this question. Hope someone can guide me in the right direction, thanks!
Attached is a picture of the diagram.
The question is
Given AD is tangent to the circle at A.
BCD is a straight line that intersects the tangent at D.
DHK is the angle bisector of Angle ADC and it cuts AC at H and AB at K.
a) show that HD * BD = KD * AD
* meaning multiply/product.
b) show that triangle AHK is an isosceles triangle.