Thread: Need help finding volume of irregular shape

1. Need help finding volume of irregular shape

Hi,

The question reads: "A swimming pool is 15.0 m wide, 24.0 m long, 1.00 m deep at one end, and 2.60 m deep at the other end. How many cubic meters of water can it hold? (The slope on the bottom is constant."

I tried solving it by turning one of the polygonal sides into a right triangle with a 1.60 m leg (2.60 - 1.00) and a hypotenuse of 24 and a rectangle with area 24 (24.0 m x 1.00 m), added up the total area, and multiplied it by the width of the pool. Does that make sense?

Thanks!

2. Re: Need help finding volume of irregular shape

Originally Posted by KevinShaughnessy
a hypotenuse of 24. Then I just took the area of the rectangle that's left (24.0 m x 1.00 m), added up the total area, and multiplied it by the width of the pool. Does that make sense?
dont take 24 as hypotenuse

take it as another leg and find the area of triangle

(swimming pool's length is given as 24)
....followed by rectangle and multiply them with the 15m width.

Cheers

3. Re: Need help finding volume of irregular shape

Originally Posted by ADARSH
dont take 24 as hypotenuse

take it as another leg and find the area of triangle

(swimming pool's length is given as 24)
....followed by rectangle and multiply them with the 15m width.

Cheers
I swear I know what a hypotenuse is! Now I feel dumb. Thanks though, it's good to know my method made sense.

4. Re: Need help finding volume of irregular shape

modify your figure to obtain a parallepiped its volume 15x24x1.80

5. Re: Need help finding volume of irregular shape

The simplest way to handle this is to look at it "from the side". You get a trapezoid with "height" (length of the pool) 24.0 m, one "base" (depth at one end) 1.00 m. and the other "base" (depth at the other end) 2.60 m which has area (1/2)(1.00+ 2.60)(24.0). The volume is that area times the width, 15.0 m.