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Thread: Help with this problem!

  1. #1
    pajala
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    Help with this problem!

    Help with this problem.



    When the marked angles added, it is 120 degrees.
    Last edited by pajala; Mar 15th 2006 at 02:44 AM.
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  2. #2
    Math Engineering Student
    Krizalid's Avatar
    Joined
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    Santiago, Chile
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    Equilic Quadrilateral, nice!

    AKMC is cyclic 'cause $\displaystyle \measuredangle~AKC=\measuredangle~AMC=60^\circ$, then $\displaystyle \measuredangle~KMA=\measuredangle~KCA=60^\circ$. In the other hand BMJC is also cyclic, therefore $\displaystyle K,\,M,\,J$ are collinear and analogous form L.

    Try to prove the rest, is not hard.
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