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Math Help - hi, dependence of pi to dependence of diameter of square to diagonal

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    hi, dependence of pi to dependence of diameter of square to diagonal

    dependence beetwen diameter of square is ( 4 * d / sqrt(2) ) / 2 = 4 / sqrt(2) = 2,83
    compare to dependence of circle based on the same ray like square above is 2,83 to 3,14 its 0,90
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    Re: hi, dependence of pi to dependence of diameter of square to diagonal

    razera - you've posted on this same subject before. Yes, the ratio of a square's perimeter to it's diagonal is 4/sqrt(2) = 2.83. And yes, this is different than the value for pi:

     \frac {4/\sqrt{2}}{\pi} = \frac {2.8284...}{3.1416...} = 0.9003...

    But do you have a specific question?
    Last edited by ebaines; July 9th 2013 at 09:07 AM.
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    Re: hi, dependence of pi to dependence of diameter of square to diagonal

    By the way- you are also consistently using the word "ray" incorrectly. A "ray" is a line that has a specific "starting" point but then goes on infinitely. It is sometimes referred to as a half line. I suspect you mean "radius" of the circle.
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    Re: hi, dependence of pi to dependence of diameter of square to diagonal

    correction :
    dependence beetwen diameter of square is ( 4 * d / sqrt(2) ) / d = 4 / sqrt(2) = 2,83
    compare to dependence of circle based on the same ray like square above is 2,83 to 3,14 its 0,90
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    MHF Contributor ebaines's Avatar
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    Re: hi, dependence of pi to dependence of diameter of square to diagonal

    I think the OP is using the term "ray" to mean the diagonal of the square and the diameter of the circle:

    hi, dependence of pi to dependence of diameter of square to diagonal-perimeter.jpg
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    Re: hi, dependence of pi to dependence of diameter of square to diagonal

    Quote Originally Posted by razera View Post
    correction :
    dependence beetwen diameter of square is ( 4 * d / sqrt(2) ) / d = 4 / sqrt(2) = 2,83
    compare to dependence of circle based on the same ray like square above is 2,83 to 3,14 its 0,90
    Yes, that's true. But what is your point in posting this?
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