# Finding x and y of an angle.

• Jun 20th 2013, 09:53 PM
Cake
Finding x and y of an angle.
Given:

Ray ST bisects angle RSV
m angle RST = x + y
m angle TSV = 2x - 2y
m angle RSV
= 64°

Find: x and y

First, I tried isolating x or y by multiplying 2 (x + y) so I can get 2x + 2y. Then I get 4x = 64?
Not sure. I am completely lost. I don't know whether to combine x + y + 2x - 2y = 64 or substitute.

The answers are x = 24 and y = 8.
• Jun 21st 2013, 12:45 AM
chiro
Re: Finding x and y of an angle.
Hey Cake.

Can you outline what the equations correspond to? Are they the lines that intersect each other? It is a little hard to follow from your description.
• Jun 21st 2013, 03:01 AM
Plato
Re: Finding x and y of an angle.
Quote:

Originally Posted by Cake
Given: Ray ST bisects angle RSV
m angle RST = x + y
m angle TSV = 2x - 2y
m angle RSV = 64°
Find: x and y

The answers are x = 24 and y = 8.

From the given you know that
$\\ x+y=32^o\\2x-2y=32^o$
• Jun 21st 2013, 09:59 AM
Cake
Re: Finding x and y of an angle.
Yeah, I didn't know when you have "bisects" you automatically take half of the measure of the whole angle.
• Jun 21st 2013, 10:36 AM
Plato
Re: Finding x and y of an angle.
Quote:

Originally Posted by Cake
Yeah, I didn't know when you have "bisects" you automatically take half of the measure of the whole angle.

What kind of geometry study are you doing?
All of geometry totally depends upon definitions.
Never try to do a geometry problem if you have any doubt about the definition of any term used in the question.
• Jun 21st 2013, 04:39 PM
Cake
Re: Finding x and y of an angle.
I am doing college level plane geometry. I spent an hour trying to figure out this problem but couldn't figure out that I had to equal them to 32.
• Jun 21st 2013, 05:11 PM
Plato
Re: Finding x and y of an angle.
Quote:

Originally Posted by Cake
I am doing college level plane geometry. I spent an hour trying to figure out this problem but couldn't figure out that I had to equal them to 32.

Well in common English bisect means to divide is half. Look it up in a standard dictionary.