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Math Help - experimenting with a cirlce

  1. #1
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    experimenting with a cirlce

    experimenting with a cirlce-circle.jpeg
    I wanted to see if I could take the top half of a unit circle and create a right triangle such that one side is equal to the circle's diameter and the other equal to half that. I think I've shown that you can't create such a triangle using the contraint of a circle.
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  2. #2
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    Re: experimenting with a cirlce

    Sorry, can't read it.
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    Re: experimenting with a cirlce

    if you click on it twice it should bring up a full screen (it does for me). Sorry about that, I'll redo it if anything.
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    Re: experimenting with a cirlce

    experimenting with a cirlce-circle2.jpegthe problem is one of creating a right triangle using the diameter as the horizontal side and letting the other two sides (hypotenuse and the vertical side equal half the circumference = Pi if radius = 1). The question is: is that possible? I think the answer is no.

    I calculated that you can't create a right triangle with

    radius=1,
    base = 2r,
    height = r

    and have the hypotenuse and the vertical side sum to pi. I would like to know if I was wrong or not.
    Last edited by kingsolomonsgrave; May 15th 2013 at 07:59 PM.
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    Re: experimenting with a cirlce

    experimenting with a cirlce-screen-shot-2013-05-16-12.00.38-am.png
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  6. #6
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    Re: experimenting with a cirlce

    You are very right it is just not possible. the reason is if one side is of right triangle is of length 2r ( diameter ) and other r 9 radius ) the hypotenuse will definitely be greater than the diameter and so will take the third vertex outside the circle.
    Thanks from kingsolomonsgrave
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