# Thread: experimenting with a cirlce

1. ## experimenting with a cirlce

I wanted to see if I could take the top half of a unit circle and create a right triangle such that one side is equal to the circle's diameter and the other equal to half that. I think I've shown that you can't create such a triangle using the contraint of a circle.

2. ## Re: experimenting with a cirlce

Sorry, can't read it.

3. ## Re: experimenting with a cirlce

if you click on it twice it should bring up a full screen (it does for me). Sorry about that, I'll redo it if anything.

4. ## Re: experimenting with a cirlce

the problem is one of creating a right triangle using the diameter as the horizontal side and letting the other two sides (hypotenuse and the vertical side equal half the circumference = Pi if radius = 1). The question is: is that possible? I think the answer is no.

I calculated that you can't create a right triangle with

radius=1,
base = 2r,
height = r

and have the hypotenuse and the vertical side sum to pi. I would like to know if I was wrong or not.

6. ## Re: experimenting with a cirlce

You are very right it is just not possible. the reason is if one side is of right triangle is of length 2r ( diameter ) and other r 9 radius ) the hypotenuse will definitely be greater than the diameter and so will take the third vertex outside the circle.