# Polygon exterior angle challenge problem

• Apr 16th 2013, 02:47 PM
tcc
Polygon exterior angle challenge problem
So my geometry teacher gave me a problem worth extra credit, and I really need the points because for some reason, im just horrible at math. I have a low B and need a boost so I can make it through the year. Heres the problem, it confuses me and I have no idea how to do it. "How many sides does a polygon have it its exterior angles are 6, 6 1/11 6 2/11, 6 3/11..up to 6 11/11". I asked him after school to give me a little bit more help and he said that 6 11/11 would make 7 and then it would go to 7, then 7 1/11 2/11 and so on up until 8, then 8 1/11..yeah. But im still not getting it =s Can anybody help? Also he wanted me to explain how I figured it out, so that would be great that if should anybody find thr answer, an explanation comes with it. Thanks =)
• Apr 16th 2013, 06:32 PM
chiro
Re: Polygon exterior angle challenge problem
Hey tcc.

Hint: What do the sum of the exterior angles equal? What does that say about the number of sides?
• Apr 16th 2013, 08:27 PM
ibdutt
Re: Polygon exterior angle challenge problem
What soever might be the number of sides of a polygon, the sum of its exterior angle is always 360 degree.The sum of interior angles of a polygon of sides n is (n-2) pi
• Apr 16th 2013, 11:02 PM
tcc
Re: Polygon exterior angle challenge problem
Ah, now that I thought about it and you guys clarified some things I think I know how to do it! Thanks for your help =)
• Apr 16th 2013, 11:21 PM
tcc
Re: Polygon exterior angle challenge problem
So what I did was convert the fractions to decimals and continue to add until I got 360..at least that was the plan. When I finished calculating the decimals they only added up to 359.809 and a total of 36 sides. Did I at least set the problem up right, and then make a calculating error?
• Apr 17th 2013, 04:29 PM
tcc
Re: Polygon exterior angle challenge problem
Nevermind, solved
• Apr 22nd 2013, 11:43 PM
first123
Re: Polygon exterior angle challenge problem
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