## Differentiation Help

Given that $y = 2^{x}$ and using the result $2^{x}= e^{xln2}$, or otherwise,

show that

$\frac{dy}{dx}= 2^{x}ln2$

Then find the gradient of the curve with equation $y= 2^{(x^{2})}$ at point (2,16)

Cheers