ABC is a triangle with ∠BAC=60∘,AB=5 and AC=25. D is a point on the internal angle bisector of ∠BAC such that BD=DC. What is AD^2?
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Apply the cosine law in the triangles ABD and ADC with BD^2 and DC^2 and then equalize them ...substitute whatever it can be substituted and at the end you will end up with AD = 5XSQROOT(3). Then AD^2 = 75.
It is not stated that D lies on AC and ahead of it, the answer wrong too.
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