Yes, that's the idea.

No, that would give you theb) find an equation for the normal to the curve at point where t = 1

this would just be substituting t=1 into the x, y and dy/dx equations and using (y-y1) = m(x-x1), yeah?tangentto the curve. The normal is perpendicular to the tangent line.

Your parametric equations are and .c) show that the cartesian equation of the curve can be written in the form

unsure on this

Solve each of those equations for t, set them equal, and solve for y.