Thread: Mass along a wire?

I have no idea how i should solve this problem..

http://snag.gy/L6hWl.jpg

Please help.. I seriously have no idea..

From the definition of dr


Take the magnitude of dr




You can find the values of in terms of t easily. Then get |dr| on its own and integrate it between t=0 and t=1

Edit. Didnt see that the density wasn't constant.
After you get an expression for dr in the form |dr|=g(t)dt since the density is 1+t find the integral of (1+t)g(t)dt between 0 and 1

After you get an expression for dr in the form |dr|=g(t)dt?..

what do you mean by numeric form of it, and g(T)?

m=int(density*sqrt((x'(t))^2+(y'(t))^2+(z'(t))^2)d t

Originally Posted by peysy

m=int(density*sqrt((x'(t))^2+(y'(t))^2+(z'(t))^2)d t

This is the length of the wire not the mass

Originally Posted by peysy

m=int(density*sqrt((x'(t))^2+(y'(t))^2+(z'(t))^2)d t

This is the length of the wire not the mass

No, with that "density" function in there, it is the mass.

density=(1+t) g/u =)

Originally Posted by HallsofIvy

No, with that "density" function in there, it is the mass.

I realise that. I included the density function in the integration in my first reply, I was preventing op from getting muddled between the two answers.