AB and AC are equal chords of a circle. AD and BE are parallel chords through A and B respectively. Prove that AE is parallel to CD. Please help!
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Originally Posted by job AB and AC are equal chords of a circle. AD and BE are parallel chords through A and B respectively. Prove that AE is parallel to CD. Please help! Of course, you have drawn a diagram? If I were you, I would work to show that $\displaystyle m(\angle EAC) = m(\angle ACD)$. There $\displaystyle m(\angle EAC)$ stands for the measure of the angle. Recall that cords of equal length subtend arcs of equal measure.
Yes thank you for your suggestion but worked it out soon after posting the message. Thanks anyway!
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