AB and AC are equal chords of a circle. AD and BE are parallel chords through A and B respectively. Prove that AE is parallel to CD. Please help!
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AB and AC are equal chords of a circle. AD and BE are parallel chords through A and B respectively. Prove that AE is parallel to CD. Please help!
Of course, you have drawn a diagram?Quote:
Originally Posted by job
If I were you, I would work to show that $\displaystyle m(\angle EAC) = m(\angle ACD)$.
There $\displaystyle m(\angle EAC)$ stands for the measure of the angle.
Recall that cords of equal length subtend arcs of equal measure.
Yes thank you for your suggestion but worked it out soon after posting the message. Thanks anyway!
