Results 1 to 3 of 3

Thread: Find Dimensions of a Log

  1. #1
    Member BobBali's Avatar
    May 2010

    Find Dimensions of a Log

    Good day to All,

    The question asked what are the dimensions of a square that can be cut from a cross-section of a tree log. The diameter of the log is given as 40cm. In my pic below it may not look like a square, but it is; sorry for the error produced in drawing it.

    So, what i first deduced is that if x cm of equal length is cut to make a square, we are left with a square of dimensions (40-2x).
    Then i found the area of the log's cross-section using:

    $\displaystyle A= \pi (r)^2. This is = 1257cm^2$

    Then I used length x width = Area to make a quadratic equation to solve for x:

    $\displaystyle (-2x+40)(-2x+40) = 1257$
    $\displaystyle 4x^2 - 160x +1600=1257$
    $\displaystyle 4x^2 -160x +343= 0$

    Solving the Quad equ gives: x = 37.4 or 2.3 (37.4 exceeds)
    The logical ans is 2.3, So> 40 - 2(2.3)= 36.4 cm
    However, the ans is 33.9cm...
    Thanks in advance.
    Attached Thumbnails Attached Thumbnails Find Dimensions of a Log-log-question.png  
    Follow Math Help Forum on Facebook and Google+

  2. #2
    MHF Contributor
    Sep 2012

    Re: Find Dimensions of a Log

    Hey BobBali.

    The thing where you slipped up was when you equated the area of the circle with the area of the square: you need to account for the left over area.

    I am going to use a technique involving integration to get the value of the square length.

    Let x^2 + y^2 = r^2 denote the relationship of a circle at the origin with radius r. We will now solve a boundary value problem where

    2*Integral (-r,r) SQRT(y^2 - x^2)dx = Area_Of_Circle = x^2 + LeftOverArea = 400*pi.

    The "LeftOverArea" is the area that is not part of the square, but part of the circle.

    We have 2*[Integral(-r,-r+y0)SQRT(r^2 - x^2)dx + Integral(r-y0,r)SQRT(r^2 - x^2)dx] = LeftOverArea = 400*pi - x^2

    By solving LeftOverArea, we solve x, and do to this, we solve for y0 where x = r - y0.

    I will complete this a little later on, but if you can pick up where I am going with this then feel free to complete it yourself.
    Follow Math Help Forum on Facebook and Google+

  3. #3
    Super Member
    Nov 2007
    Trumbull Ct

    Re: Find Dimensions of a Log

    using simple geometry I get an answer of 28.3 cm
    Follow Math Help Forum on Facebook and Google+

Similar Math Help Forum Discussions

  1. Find Dimensions of a Log
    Posted in the Geometry Forum
    Replies: 4
    Last Post: Feb 6th 2013, 05:56 AM
  2. Find dimensions of box
    Posted in the Algebra Forum
    Replies: 1
    Last Post: Mar 29th 2010, 01:10 AM
  3. find the the dimensions of x and y
    Posted in the Calculus Forum
    Replies: 3
    Last Post: Dec 3rd 2009, 09:39 AM
  4. Find the dimensions
    Posted in the Algebra Forum
    Replies: 1
    Last Post: Jun 10th 2009, 03:42 PM
  5. Find Dimensions of Rectangle
    Posted in the Pre-Calculus Forum
    Replies: 2
    Last Post: Nov 8th 2008, 09:13 PM

Search Tags

/mathhelpforum @mathhelpforum