Thanks!
Hello, Jammix!
Is there any more information?
I suspect that I know the solution . . . but it's only a guess.
Circumscribe a square about a semicircle.
Square is circumscribed about the (tilted) semicircle.Code:R B * - -.-.*.o.*.-.- * C | .*:::::|:::::*.| | *:::::::|:::::::o S |*::::::::|:::::* | |:::::::::|:::* r | *:::::::::|:* * Q o:-:-:-:-:O - - - o *:::::::* : * |:::::*r : | | ::* : | A * o - - - * - - - * D P E
The circle has center and radius
is an isosceles right triangle.
Hypotenuse
Let , the side of the square.
Then: .
Therefore: .