Diagram: http://i50.tinypic.com/2n19jpe.png
Given: Triangle ABC is isosceles with AC congruent to BC.
AC is extended to D.
Prove: AD > DB
It's Problem #3 on page 2:
http://stuy.enschool.org/pdf/forms/c...ms/MG21_11.pdf
Does this help?
Of course it does not help. That does not give a detailed list of axioms nor a detailed list of theorems.
I gave you the general solution. There is usually a theorem that states: In a triangle, if two angles have different measures then the longer side is opposite the larger angle. Now there are all sorts of ways to prove that. BUT each way depends upon the particular axiom set in use. We have no way to know that.
We have no way to know that.
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