Length of old lot = width + 100

Area of old lot = width * (width + 100)

Area of new lot = 2 * width * (width + 100)

Since the width of both lots are the same, the 2 must go with the length,

Area of new lot = width *[2(width+100)]

The length of the new lot is 2*(width+100), the width is the same

Now the hard one,

1200 = xy where x is side of aluminum, y is the side with steel

20(2x) + 10(2y) = 2200 note we multiply by 2 since there are two sides each

40x + 20y = 2200

Now, we have a quadratic equation, y = 1200/x

40x + 20(1200/x) = 2200 multiply everything by x

40x^2 + 24000 = 2200x

40x^2 -2200x + 24000 = 0

Now use the quadratic formula and you get x, then plug in to y = 1200/x