I don't know how to approach the problem.

Draw triangle ABC, with P the midpoint of AB, Q the midpoint of BC, and R the Midpoint of CA. If X is any point , show that XA + XB + XC = XP + XQ + XR

Thanks!

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- Jan 3rd 2013, 03:02 PMea22224Vector Geometry
I don't know how to approach the problem.

Draw triangle ABC, with P the midpoint of AB, Q the midpoint of BC, and R the Midpoint of CA. If X is any point , show that XA + XB + XC = XP + XQ + XR

Thanks! - Jan 3rd 2013, 03:08 PMPlatoRe: Vector Geometry
- Jan 15th 2013, 04:19 PMea22224Re: Vector Geometry
so i wrote that XP = XA + AP and XP = XB - PB

AP = PB so i combined the two equations to ge 2XP = XA + XB

and that 2XR = XA +XC and 2XQ = XB + XC

adding the three equations together, i got 2XA +2XB + 2XC = 2XP + 2 XR + 2XQ and then simplified.

Am I doing it right, or did i miss something - Jan 15th 2013, 05:23 PMHallsofIvyRe: Vector Geometry
I think I would be inclined to start with the obvious: AB+ BC= AC. Then divide both sides by 2.

- Jan 15th 2013, 09:35 PMrichard1234Re: Vector Geometry
Edit: Whoops, I might have misinterpreted vectors as lengths of segments (if XA referred to the length of XA, as opposed to vector XA, the problem would be clearly flawed).

- May 5th 2013, 12:10 PMmaliwaltersRe: Vector Geometry
Did you figure out the answer...........I am trying to do the same problem...............some help and clarification would be much appreciated!!