triangle ABC has its coordinates at A(a, -1) , B(8,-1) , C(5,4). If the base is twice the
height, find a.
can anybody do me a favor on this problem...
thanks a lot
If we assume the base lies along the line $\displaystyle y=-1$, then what is the vertical distance (the altitude of the triangle) from point $\displaystyle C$ to this line?
Once you find the altitude, then what are the $\displaystyle x$-coordinates of the two points on the base line whose distance from point $\displaystyle B$ is twice the altitude?
I suppose the base is intended to be AB, (but it depends on which way you choose to look at it, a badly worded question), so, since A and B have the same y coordinate, the base length will be the difference between their x coordinates.
Also, since A and B have the same y coordinate, it's easy to work out the height of the triangle.
All that's left is to say the base length is double the height and to solve the resulting equation.