Find the equation of the tangent to the circle x^2 + y^ - 8y = 0 if the
point of tangency is (0,8).
My ATTEMPT: i solved for the center of the circle from the equation of the circle...
x^2 + y^2 - 8y = 0
x^2 + ( y - 4)^2 = 16
so, center ( 0, 4)
since point of tangency is ( 0,8) ...
im stuck here ...
because i wanted to find the slope of the segment (radius) joining the center and the point of tangency, so that after that I i would be able to solve the line perpendicular to the radius of the circle.
Can anybody help me on this please.