Find the equation of the tangent to the circle x^2 + y^ - 8y = 0 if the

point of tangency is (0,8).

My ATTEMPT: i solved for the center of the circle from the equation of the circle...

x^2 + y^2 - 8y = 0

x^2 + ( y - 4)^2 = 16

so, center ( 0, 4)

since point of tangency is ( 0,8) ...

im stuck here ...

because i wanted to find the slope of the segment (radius) joining the center and the point of tangency, so that after that I i would be able to solve the line perpendicular to the radius of the circle.

Can anybody help me on this please.