Hello, really stuck on this problem, any help welcome
AB is parallel to CD, this distance between them is X
The square has side length X
Prove that the angle shown on the diagram is 45 degrees
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Can you give the diagram?
How is that?
You aren't given an angle of rotation for the square?
thats all the information that is given i am afraid
I could be wrong, but it seems to me the angle marked in the diagram depends on the angle of rotation of the square.
it does not unfortunately, provided that a bit of the square is above and below the line then this will always be true
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