Hello, really stuck on this problem, any help welcome
AB is parallel to CD, this distance between them is X
The square has side length X
Prove that the angle shown on the diagram is 45 degrees
Thank you
Rhys
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Hello, really stuck on this problem, any help welcome
AB is parallel to CD, this distance between them is X
The square has side length X
Prove that the angle shown on the diagram is 45 degrees
Thank you
Rhys
Can you give the diagram?
How is that?
Thanks
You aren't given an angle of rotation for the square?
thats all the information that is given i am afraid
I could be wrong, but it seems to me the angle marked in the diagram depends on the angle of rotation of the square.
it does not unfortunately, provided that a bit of the square is above and below the line then this will always be true
