The radius of circle ABC, centre B is r1. The radius of circle CDE, centre D is r2. For the diagram above PROVE that AC/CE = r1/r2 :l
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This is a picture
Hint: There are some similar triangles in the diagram...
How about this pic attached. $\displaystyle \frac{\sqrt(2)*r1}{\sqrt(2)*r2} = \frac{r1}{r2} $
Jakncoke, I dont quite understand where and how you got those figures could you please explain?
@jakncoke, that's only a specific case (for right isosceles triangles). It does generalize, using similarity.
yea my bad, i wasn't thinking.
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