Results 1 to 3 of 3

Math Help - please help me

  1. #1
    Newbie
    Joined
    Oct 2012
    From
    Pune
    Posts
    3

    please help me

    Hello friends ,
    I am solving this question:

    The sum of how may tersm of the series 6 + 12 + 18 + 24 + ... is 1800 ?

    where I came across this equation n^2+n-600=0

    got the values n=24 or n=25

    but i dident understood how to put these values in the eqn as the answer is
    ie sum of the terms = only 24

    and the question is
    sum of how may tersm of the series 6 + 12 + 18 + 24 + ... is 1800?

    so how to calcullare sum of the terms ?
    so please help me

    thanks..............
    Follow Math Help Forum on Facebook and Google+

  2. #2
    Super Member
    earboth's Avatar
    Joined
    Jan 2006
    From
    Germany
    Posts
    5,830
    Thanks
    123

    Re: please help me

    Quote Originally Posted by manishamishra View Post
    Hello friends ,
    I am solving this question:

    The sum of how may tersm of the series 6 + 12 + 18 + 24 + ... is 1800 ?

    where I came across this equation n^2+n-600=0

    got the values n=24 or n=25 <-- this is wrong: The 2nd solution is n = -25 and therefore invalid with your problem

    but i dident understood how to put these values in the eqn as the answer is
    ie sum of the terms = only 24

    and the question is
    sum of how may tersm of the series 6 + 12 + 18 + 24 + ... is 1800?

    so how to calcullare sum of the terms ?
    so please help me

    thanks..............
    .....
    Follow Math Help Forum on Facebook and Google+

  3. #3
    MHF Contributor
    skeeter's Avatar
    Joined
    Jun 2008
    From
    North Texas
    Posts
    12,061
    Thanks
    900

    Re: please help me

    Follow Math Help Forum on Facebook and Google+


/mathhelpforum @mathhelpforum