help about right triangles!
i have question about right triangles and perimeter:
"If the perimeter of a right triangle is 12 and it's hypotenuse is 5, what is the area of the triangle?"
formula for area: a=bh/2
perimeter = b+h+hypotenuse = 12
this is solved by substitution?
Re: help about right triangles!
Let and be the two legs of the right triangle. Since the perimeter is 12 and the hypotenuse is 5, we know:
By the Pythagorean theorem, we also know:
I recommend squaring the first equation to find , since the second equation gives you the value of the sum of the squares of the legs.