# area bounded

• Sep 15th 2012, 09:25 AM
rcs
area bounded
What is the Area bounded by x^2 = y, x = 1 , and x - axis?

what does this mean? favor please

thanks
• Sep 15th 2012, 09:32 AM
HallsofIvy
Re: area bounded
Quote:

Originally Posted by rcs
What is the Area bounded by x^2 = y, x = 1 , and x - axis?

what does this mean? favor please

thanks

Have you at least graphed those? You should have a parabola (y= x^3), a vertical line (x= 1), and a horizontal line (y= 0, the x-axis). Do you see the region bounded by those? Do you see that you are asked for the area "below" y= x^2 betweeen x= 0 and x= 1? Since you are asking a question like this, I take it you are taking a Calculus class. And you should have learned that the "area below y= f(x), between x= a and x= b" is given by the integral $\displaystyle \int_a^b f(x)dx$. That is the simplest application of the integral and, in fact, is usually used to introduce the integral.
• Sep 15th 2012, 04:30 PM
rcs
Re: area bounded
you are only giving things with the same concept of the my math problem but you either cannot answer :)
• Sep 15th 2012, 04:53 PM
skeeter
Re: area bounded
Quote:

Originally Posted by rcs
What is the Area bounded by x^2 = y, x = 1 , and x - axis?

what does this mean? favor please

$\displaystyle \int_0^1 x^2 \, dx = \frac{1}{3}$

http://mathandmultimedia.com/wp-cont...ogebra18-1.png
• Sep 15th 2012, 10:21 PM
MarkFL
Re: area bounded
Quote:

Originally Posted by rcs
you are only giving things with the same concept of the my math problem but you either cannot answer :)

The user you are addressing here is a valuable contributor on several forums that I know of personally, and probably several that I do not know of. I have gained insight many times from reading his posts. When you imply that the solution is beyond him, I can but chuckle, yet your demeanor here recently is no laughing matter.

I'm not trying to bust your chops, but please treat the folks here with more respect.

He is giving you the concept needed to answer the question in the hope that you may apply it yourself, and gain an understanding from the application.
• Sep 16th 2012, 12:48 AM
rcs
Re: area bounded
Quote:

Originally Posted by MarkFL2
The user you are addressing here is a valuable contributor on several forums that I know of personally, and probably several that I do not know of. I have gained insight many times from reading his posts. When you imply that the solution is beyond him, I can but chuckle, yet your demeanor here recently is no laughing matter.

I'm not trying to bust your chops, but please treat the folks here with more respect.

He is giving you the concept needed to answer the question in the hope that you may apply it yourself, and gain an understanding from the application.

i respect anyone here unless they do something not good in my feelings. thanks MArky