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Math Help - How to find other length of the base on a Trinagle?

  1. #1
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    How to find other length of the base on a Trinagle?

    How to find other length of the base on a Trinagle?-triangle-2-calculus.png
    Hi, I was confused on with this triangle.
    At first I thought I should've started off with Pythagoras' Therom
    I got the square root of (x2+180) = c
    After I got c, I didn't know if it mattered.

    I tried getting the smaller triangle's hypotenuse, which is the square root of (4 + x2) = 2 + x
    After that, I made the 2 hypotenuses equal to equal other
    2 + x = square root of (x2 + 180)
    4 + x2 = x2 + 180
    Yeah.. I got lost here since I will be losing x...
    Can someone give me a tip or explain? Thanks
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  2. #2
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    Re: How to find other length of the base on a Trinagle?

    Quote Originally Posted by Chaim View Post
    Click image for larger version. 

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    \frac{x+12}{6}=\frac{x}{2}
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  3. #3
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    Re: How to find other length of the base on a Trinagle?

    side lengths of similar triangles are proportional ...

    \frac{6}{12+x} = \frac{2}{x}
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