Hi there, Need some help with this circle geometry question: Point P is marked inside a regular hexagon ABCDEF so that Angle BAP = Angle DCP = 50 degrees. Find the size of angle ABP. Thanks!
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ABP=80 deg
Last edited by MaxJasper; Sep 9th 2012 at 01:20 AM.
Originally Posted by MaxJasper ABP=80 deg Care to elaborate? What theorems? How did you arrive at that conclusion?
We know that the interior angles of a regular hexagon are 120 degrees. The triangles with apex P are congruent by side-angle-side. So all the base angles are 50d or 70d. So angle ABP is 70 degrees
How do you know that the triangles are congruent? They are most certainly not. Only one side is equal in each of the triangles, that is all you know.
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