Find the coordinates of the points on the curve X^2 -2xy+2y^2=4 at which the tangent is parallel to x-axis.
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Find the coordinates of the points on the curve X^2 -2xy+2y^2=4 at which the tangent is parallel to x-axis.
Use implicit differentiation to findQuote:
Originally Posted by Minwoo
.
Next solve.
Yes, I found dy/dx is (x-y)/(x-2y), then what is the next step? Thank you
At what points on the curve is it true thatQuote:
Originally Posted by Minwoo
Sorry, I really dunno
Are you saying that you cannot solveQuote:
Originally Posted by Minwoo
If you are, then you have no business even trying this problem!
You don't really have to find the derivative explicitely. Going back to your original equation,, implicit differentiation gives
. Now, because you are looking for points where y'= 0, put y'= 0 into that equation:
. That tells you that y= x. Replace y with x in the original equation,
Thank you for the help