I need to know the value of s and a. S is the side length of the hexagon and a is the smallest width.

The only value I know is A = 48” (inches) and the circumradius which is also 48”.

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- Sep 5th 2012, 10:48 AMcadenlyon2002hexagon please help!!
I need to know the value of s and a. S is the side length of the hexagon and a is the smallest width.

The only value I know is A = 48” (inches) and the circumradius which is also 48”. - Sep 5th 2012, 01:16 PMSorobanRe: hexagon please help!!
Hello, cadenlyon2002!

Quote:

I need to know the value of $\displaystyle s$ and $\displaystyle a$.

$\displaystyle S$ is the side length of the hexagon and $\displaystyle a$ is the smallest width.

The only value I know is $\displaystyle A$ = 48 inches, and the circumradius which is also 48 inches.

Could you provide the original wording of the problem?

As given, it's both sloppy and incorrect.

Is it ahexagon? .It should say so ... clearly.*regular*

There seems to be four variables: $\displaystyle S,\,s,\,A,\,a.$

If the smallest width is 48, the circumradius is48.*not*

Are you also known as "september.cooper"?

It doesn't matter.

See my response to him/her at FMH.

- Sep 26th 2012, 01:14 AMmanoj9585Re: hexagon please help!!
I think at the time math is very difficult subject, parents should help kids in solving math problems. and about 6 sided I want to share a simple definition as-6 sided polygon is called as Hexagon, This is one type of regular polygons, it may be regular or irregular. It’s a 6 sided closed figure.

solve my math problem - Sep 26th 2012, 06:22 AMHallsofIvyRe: hexagon please help!!
I suggest

**you**be more careful. You cannot say a hexagon "is one type of**regular**polygons" and then say "it may be regular or irregular". In any case, I see no reason to think that cadenlyon2002 did NOT know what a "hexagon" is. Yes, a hexagon is a closed, 6-sided,**two-dimensional**figure.**If**all 6 sides have the same length and all 6 angles are the same, then the hexagon is "regular" and**then**it is 'one type of regular polygon'.