Just solve for L. How would you find L?
Once you've found L, find 2L - 1, then find the diagonal via Pythagorean theorem.
The width of a rectangle is 1 less than twice its length. If the area of the rectangle is 40 cm, what is the length of the diagonal?
Note: Your answer must be a number. It may not contain any arithmetic operations.
The length of the diagonal is....
I need help with this problem :/
the width is = 2L - 1
length is L
so.... (2L-1)(L) = 40
2L^2 - 1L = 40
2L^2 - 1L - 40 = 0