1st tank bottom is 6" higher than the 2nd.
v1 = 4*5*2.5
v2 = 4*7*3
1/2*(v1+v2) = 67 = vol of water in both tanks.
h = elevation of water in larger tank:
67 = 4*5*(h-.5) + 4*7*h
h = 1.6042'
Hey guys , please kinda show me the solution for this problem .
The Answer is 77/48 ft.
Two rectangular water tanks with tops on the same level are connected by a pipe through their bottoms. The base of one is 6 in. higher than that of the other. Their dimensions are 4 by 5 by 2 1/2 ft, and 4 by 7 by 3 ft., respectively. How deep is the water in the larger tank when the water they contain equals half their combined capacity, if the 2 1/2 ft. and 3 ft. edges are vertical?
THANKS MUCH !!