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Math Help - Looking for help

  1. #1
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    Looking for help

    Can anyone help me with this question. 1998 x abc = cba x 8991?
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  2. #2
    MHF Contributor

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    Re: Looking for help

    That is not a "question", it is an equation. The question is "what do you want to do with that equation?"
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  3. #3
    Senior Member MaxJasper's Avatar
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    Lightbulb Re: Looking for help

    Two values:
    abc ={81, 891}

    Other values up to 1000,000
    abcdef= {81, 891, 8181, 8991, 81081, 89991, 810081, 818181, 891891, 899991}

    You can solve:

    1998*(c+10b+100a)=8991*(a+10b+100c)

    a=(70b+898c)/191 :: 70b+898c=0 mod(191) ==> b=9, c=1, a=8 ==> abc=891
    Last edited by MaxJasper; August 26th 2012 at 07:13 PM.
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