Can anyone help me with this question. 1998 x abc = cba x 8991?


Two values:
abc ={81, 891}
Other values up to 1000,000
abcdef= {81, 891, 8181, 8991, 81081, 89991, 810081, 818181, 891891, 899991}
You can solve:
1998*(c+10b+100a)=8991*(a+10b+100c)
a=(70b+898c)/191 :: 70b+898c=0 mod(191) ==> b=9, c=1, a=8 ==> abc=891