Find the area of triangle

Hello everyone, pls help me with this problem. Thanks in advance!

Three unit circles are arranged side by side in a row. A is the point on the first circle

that is collinear with the centers of the three circles which does not touch the second circle. The lines AB and AC are tangent

to the third circle at the points B and C. Find the area of ABC.

Re: Find the area of triangle

Let O be the center of the third circle. Triangle ABO is right. From it you can find AB and angle BAO, which is half of angle BAC.

Re: Find the area of triangle

Re: Find the area of triangle

A geometric solution ( reference Soroban's solution)

Let D = intersection of BC and AO

BO =1 AO =5 AB= rad 24

Triangle ABO is a rt triangle @ B. BD is the altitude on AO

let DO = x AD = 5-x

AB^2 /BO^2 = 5-x/x

24/1 = 5-x /x whence x=1/5 and 5-x= 24/5

BD^2 = 24/5 *1/5

BD = rad 24/5

area of ABC = BD * AD = rad24 *24/25

The relationships of sides and hypot segments of a rt triangle created by BD and that of the segments to the altitude are standard theorems