Problem solved, get it now
Sorry for the trouble =x
I am stucked on a question on my homework. Here is the problem:
The diagonals of a rectangle are 8 units long and intersect at a 60 degree angle. Find the dimensions of the rectangle.
What I dont get is , what is "dimension"? This is supposed to be about the "Special Right Triangle" (30-60-90) (45-45-90) Theorems.
Any help will be appreciated. Thank you!
My answer is one side is 4, and the other side is 4 Square Root of 3
(Not sure if its correct or not though)
Here will help it easier:
The diagonal intersect at 60 degree, which is an equilateral triangle. Since it is an equilateral triangle which means all the 3 sides are the same length. The diagonal length is 8 units, the diagonal of rectangle bisects each other, which is 8/2=4 Thus one side is 4. So now we know one dimension of this rectangle, for the other side. Look at the bigger triangle.
(The blue outlined one)
We can see a right angle, and a 60 degree angle, which automatically marks the other one 30 degree angle. So we can use the 30-60-90 Theorem, Since we know one side is 4 unites, the Hyp is 8 units, to find out the other leg, use the equation, Longer leg = Shorter leg x Square Root of 3. We already know the shorter leg is 4, thus 4 x Square Root of 3 = 4 Square Root of 3
Once again, thank you for clear up the question for me =)))