Express the following equations in a form suitable for drawing a straight line graph, stating its axes, gradient and vertical intercept.
1. y = e^(ax + by)
2. y = (a / b)^(xy + 1)
Express the following equations in a form suitable for drawing a straight line graph, stating its axes, gradient and vertical intercept.
1. y = e^(ax + by)
2. y = (a / b)^(xy + 1)
Assuming that a and b are unknown constants to be determined ?
For the first relationship, take logs
and then divide by (you could also divide by , that would lead to an alternative equation),
Then construct the new variables and
That will give you the straight line which has a slope of and an intercept of
You can do a similar thing with the second example.
For the second question, this is what I did:
lg y = (xy + 1)(lg a - lg b)
lg y = xy lg a - xy lg b + lg a - lg b
lg y = (lg a/b)xy + lg a/b
So the Y-axis = lg y, X-axis = xy, gradient = lg a/b and vertical intercept = lg a/b
Is this correct?