You can easily use the "formula" for the distance between a point and a line. For example, you have so you know that the point (0,-2) is on the line. So use the formula to find the distance between (0,-2) and the line .
Or, you can skip the formula and draw the graph. Use geometry.
1 graph the lines
2 erect a vertical line @x=1. Apoint (1,1) on line y=3x-2 is produced
3@(1,1) erect a perpendicular to y=3x+3
4 write an equation for the perpendicular
5 solve for intersection of 4 and y=3x +3
6 use distance formula to find question d
d^2 = delta y^2 + delta x^2 (slope diagram between (1,1) and solution of 5 above
There is a simple solution using trig and the slope angle of the parallel lines
If you are allowed to use Trigonometry, here is another solution.
Find the exact perpendicular distance between two parallel lines: .
The two lines have y- intercepts at 3 and -2, and identical slopes.Code:| | / | / / | / / |/ / A * / : |@* / : | * / : | * C 5 | / : + - / - - - - : | / : | / : |/ @ B * - - - - E |
Draw perpendicular to the line through
Then the slope of
We have: .
is in a right triangle with:
In right triangle